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md5c語言實現

發布時間: 2021-03-13 18:43:16

❶ c語言實現文件傳輸時用md5加密

你需要先搞一個openssl的庫，然後調用相應的
md5
的函數就好了

❷ 求c語言調用md5函數的函數，注意是直接輸入字元串就能獲得的，不要輸入文件名的那種

|c語言標准庫沒有這個函數，隨便給你搜了一下別人的實現

/*md5.h*/
#ifndef MD5_H
#define MD5_H

typedef struct
{
unsigned int count[2];
unsigned int state[4];
unsigned char buffer[64];
}MD5_CTX;

#define F(x,y,z) ((x & y) | (~x & z))
#define G(x,y,z) ((x & z) | (y & ~z))
#define H(x,y,z) (x^y^z)
#define I(x,y,z) (y ^ (x | ~z))
#define ROTATE_LEFT(x,n) ((x << n) | (x >> (32-n)))
#define FF(a,b,c,d,x,s,ac) \
{ \
a += F(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
#define GG(a,b,c,d,x,s,ac) \
{ \
a += G(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
#define HH(a,b,c,d,x,s,ac) \
{ \
a += H(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
#define II(a,b,c,d,x,s,ac) \
{ \
a += I(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
void MD5Init(MD5_CTX *context);
void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputlen);
void MD5Final(MD5_CTX *context,unsigned char digest[16]);
void MD5Transform(unsigned int state[4],unsigned char block[64]);
void MD5Encode(unsigned char *output,unsigned int *input,unsigned int len);
void MD5Decode(unsigned int *output,unsigned char *input,unsigned int len);

#endif

/*md5.c*/
#include <memory.h>
#include "md5.h"

unsigned char PADDING[]={0x80,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};

void MD5Init(MD5_CTX *context)
{
context->count[0] = 0;
context->count[1] = 0;
context->state[0] = 0x67452301;
context->state[1] = 0xEFCDAB89;
context->state[2] = 0x98BADCFE;
context->state[3] = 0x10325476;
}
void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputlen)
{
unsigned int i = 0,index = 0,partlen = 0;
index = (context->count[0] >> 3) & 0x3F;
partlen = 64 - index;
context->count[0] += inputlen << 3;
if(context->count[0] < (inputlen << 3))
context->count[1]++;
context->count[1] += inputlen >> 29;

if(inputlen >= partlen)
{
memcpy(&context->buffer[index],input,partlen);
MD5Transform(context->state,context->buffer);
for(i = partlen;i+64 <= inputlen;i+=64)
MD5Transform(context->state,&input[i]);
index = 0;
}
else
{
i = 0;
}
memcpy(&context->buffer[index],&input[i],inputlen-i);
}
void MD5Final(MD5_CTX *context,unsigned char digest[16])
{
unsigned int index = 0,padlen = 0;
unsigned char bits[8];
index = (context->count[0] >> 3) & 0x3F;
padlen = (index < 56)?(56-index):(120-index);
MD5Encode(bits,context->count,8);
MD5Update(context,PADDING,padlen);
MD5Update(context,bits,8);
MD5Encode(digest,context->state,16);
}
void MD5Encode(unsigned char *output,unsigned int *input,unsigned int len)
{
unsigned int i = 0,j = 0;
while(j < len)
{
output[j] = input[i] & 0xFF;
output[j+1] = (input[i] >> 8) & 0xFF;
output[j+2] = (input[i] >> 16) & 0xFF;
output[j+3] = (input[i] >> 24) & 0xFF;
i++;
j+=4;
}
}
void MD5Decode(unsigned int *output,unsigned char *input,unsigned int len)
{
unsigned int i = 0,j = 0;
while(j < len)
{
output[i] = (input[j]) |
(input[j+1] << 8) |
(input[j+2] << 16) |
(input[j+3] << 24);
i++;
j+=4;
}
}
void MD5Transform(unsigned int state[4],unsigned char block[64])
{
unsigned int a = state[0];
unsigned int b = state[1];
unsigned int c = state[2];
unsigned int d = state[3];
unsigned int x[64];
MD5Decode(x,block,64);
FF(a, b, c, d, x[ 0], 7, 0xd76aa478); /* 1 */
FF(d, a, b, c, x[ 1], 12, 0xe8c7b756); /* 2 */
FF(c, d, a, b, x[ 2], 17, 0x242070db); /* 3 */
FF(b, c, d, a, x[ 3], 22, 0xc1bdceee); /* 4 */
FF(a, b, c, d, x[ 4], 7, 0xf57c0faf); /* 5 */
FF(d, a, b, c, x[ 5], 12, 0x4787c62a); /* 6 */
FF(c, d, a, b, x[ 6], 17, 0xa8304613); /* 7 */
FF(b, c, d, a, x[ 7], 22, 0xfd469501); /* 8 */
FF(a, b, c, d, x[ 8], 7, 0x698098d8); /* 9 */
FF(d, a, b, c, x[ 9], 12, 0x8b44f7af); /* 10 */
FF(c, d, a, b, x[10], 17, 0xffff5bb1); /* 11 */
FF(b, c, d, a, x[11], 22, 0x895cd7be); /* 12 */
FF(a, b, c, d, x[12], 7, 0x6b901122); /* 13 */
FF(d, a, b, c, x[13], 12, 0xfd987193); /* 14 */
FF(c, d, a, b, x[14], 17, 0xa679438e); /* 15 */
FF(b, c, d, a, x[15], 22, 0x49b40821); /* 16 */

/* Round 2 */
GG(a, b, c, d, x[ 1], 5, 0xf61e2562); /* 17 */
GG(d, a, b, c, x[ 6], 9, 0xc040b340); /* 18 */
GG(c, d, a, b, x[11], 14, 0x265e5a51); /* 19 */
GG(b, c, d, a, x[ 0], 20, 0xe9b6c7aa); /* 20 */
GG(a, b, c, d, x[ 5], 5, 0xd62f105d); /* 21 */
GG(d, a, b, c, x[10], 9, 0x2441453); /* 22 */
GG(c, d, a, b, x[15], 14, 0xd8a1e681); /* 23 */
GG(b, c, d, a, x[ 4], 20, 0xe7d3fbc8); /* 24 */
GG(a, b, c, d, x[ 9], 5, 0x21e1cde6); /* 25 */
GG(d, a, b, c, x[14], 9, 0xc33707d6); /* 26 */
GG(c, d, a, b, x[ 3], 14, 0xf4d50d87); /* 27 */
GG(b, c, d, a, x[ 8], 20, 0x455a14ed); /* 28 */
GG(a, b, c, d, x[13], 5, 0xa9e3e905); /* 29 */
GG(d, a, b, c, x[ 2], 9, 0xfcefa3f8); /* 30 */
GG(c, d, a, b, x[ 7], 14, 0x676f02d9); /* 31 */
GG(b, c, d, a, x[12], 20, 0x8d2a4c8a); /* 32 */

/* Round 3 */
HH(a, b, c, d, x[ 5], 4, 0xfffa3942); /* 33 */
HH(d, a, b, c, x[ 8], 11, 0x8771f681); /* 34 */
HH(c, d, a, b, x[11], 16, 0x6d9d6122); /* 35 */
HH(b, c, d, a, x[14], 23, 0xfde5380c); /* 36 */
HH(a, b, c, d, x[ 1], 4, 0xa4beea44); /* 37 */
HH(d, a, b, c, x[ 4], 11, 0x4bdecfa9); /* 38 */
HH(c, d, a, b, x[ 7], 16, 0xf6bb4b60); /* 39 */
HH(b, c, d, a, x[10], 23, 0xbebfbc70); /* 40 */
HH(a, b, c, d, x[13], 4, 0x289b7ec6); /* 41 */
HH(d, a, b, c, x[ 0], 11, 0xeaa127fa); /* 42 */
HH(c, d, a, b, x[ 3], 16, 0xd4ef3085); /* 43 */
HH(b, c, d, a, x[ 6], 23, 0x4881d05); /* 44 */
HH(a, b, c, d, x[ 9], 4, 0xd9d4d039); /* 45 */
HH(d, a, b, c, x[12], 11, 0xe6db99e5); /* 46 */
HH(c, d, a, b, x[15], 16, 0x1fa27cf8); /* 47 */
HH(b, c, d, a, x[ 2], 23, 0xc4ac5665); /* 48 */

/* Round 4 */
II(a, b, c, d, x[ 0], 6, 0xf4292244); /* 49 */
II(d, a, b, c, x[ 7], 10, 0x432aff97); /* 50 */
II(c, d, a, b, x[14], 15, 0xab9423a7); /* 51 */
II(b, c, d, a, x[ 5], 21, 0xfc93a039); /* 52 */
II(a, b, c, d, x[12], 6, 0x655b59c3); /* 53 */
II(d, a, b, c, x[ 3], 10, 0x8f0ccc92); /* 54 */
II(c, d, a, b, x[10], 15, 0xffeff47d); /* 55 */
II(b, c, d, a, x[ 1], 21, 0x85845dd1); /* 56 */
II(a, b, c, d, x[ 8], 6, 0x6fa87e4f); /* 57 */
II(d, a, b, c, x[15], 10, 0xfe2ce6e0); /* 58 */
II(c, d, a, b, x[ 6], 15, 0xa3014314); /* 59 */
II(b, c, d, a, x[13], 21, 0x4e0811a1); /* 60 */
II(a, b, c, d, x[ 4], 6, 0xf7537e82); /* 61 */
II(d, a, b, c, x[11], 10, 0xbd3af235); /* 62 */
II(c, d, a, b, x[ 2], 15, 0x2ad7d2bb); /* 63 */
II(b, c, d, a, x[ 9], 21, 0xeb86d391); /* 64 */
state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;
}

❸ 請教MD5演算法用C語言實現

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#ifdefined(__APPLE__)
#defineCOMMON_DIGEST_FOR_OPENSSL
#include<CommonCrypto/CommonDigest.h>
#defineSHA1CC_SHA1
#else
#include<openssl/md5.h>
#endif

//這是我自己寫的函數，用於計算MD5
//參數str：要轉換的字元串
//參數lengthL:字元串的長度可以用strlen(str)直接獲取參數str的長度
//返回值：MD5字元串
char*str2md5(constchar*str,intlength){
intn;
MD5_CTXc;
unsignedchardigest[16];
char*out=(char*)malloc(33);

MD5_Init(&c);

while(length>0){
if(length>512){
MD5_Update(&c,str,512);
}else{
MD5_Update(&c,str,length);
}
length-=512;
str+=512;
}

MD5_Final(digest,&c);

for(n=0;n<16;++n){
snprintf(&(out[n*2]),16*2,"%02x",(unsignedint)digest[n]);
}

returnout;
}

intmain(intargc,char**argv){
char*output=str2md5("hello",strlen("hello"));

printf("%s
",output);
//上面會輸出hello的MD5字元串：
//
free(output);
return0;
}

❹ 如何用C語言實現MD5演算法計算一個文本的消息摘要

#include<stdio.h>
#include<string.h>

#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
#define H(x, y, z) ((x) ^ (y) ^ (z))
#define I(x, y, z) ((y) ^ ((x) | (~z)))

#define RL(x, y) (((x) << (y)) | ((x) >> (32 - (y)))) //x向左循環移y位

#define PP(x) (x<<24)|((x<<8)&0xff0000)|((x>>8)&0xff00)|(x>>24) //將x高低位互換,例如PP(aabbccdd)=ddccbbaa

#define FF(a, b, c, d, x, s, ac) a = b + (RL((a + F(b,c,d) + x + ac),s))
#define GG(a, b, c, d, x, s, ac) a = b + (RL((a + G(b,c,d) + x + ac),s))
#define HH(a, b, c, d, x, s, ac) a = b + (RL((a + H(b,c,d) + x + ac),s))
#define II(a, b, c, d, x, s, ac) a = b + (RL((a + I(b,c,d) + x + ac),s))

void go_md5(unsigned *a, unsigned *b, unsigned *c, unsigned *d, unsigned *A, unsigned *B, unsigned *C, unsigned *D, unsigned x[]){ //MD5核心演算法,供64輪

*a=*A,*b=*B,*c=*C,*d=*D;
/**//* Round 1 */
FF (*a, *b, *c, *d, x[ 0], 7, 0xd76aa478); /**//* 1 */
FF (*d, *a, *b, *c, x[ 1], 12, 0xe8c7b756); /**//* 2 */
FF (*c, *d, *a, *b, x[ 2], 17, 0x242070db); /**//* 3 */
FF (*b, *c, *d, *a, x[ 3], 22, 0xc1bdceee); /**//* 4 */
FF (*a, *b, *c, *d, x[ 4], 7, 0xf57c0faf); /**//* 5 */
FF (*d, *a, *b, *c, x[ 5], 12, 0x4787c62a); /**//* 6 */
FF (*c, *d, *a, *b, x[ 6], 17, 0xa8304613); /**//* 7 */
FF (*b, *c, *d, *a, x[ 7], 22, 0xfd469501); /**//* 8 */
FF (*a, *b, *c, *d, x[ 8], 7, 0x698098d8); /**//* 9 */
FF (*d, *a, *b, *c, x[ 9], 12, 0x8b44f7af); /**//* 10 */
FF (*c, *d, *a, *b, x[10], 17, 0xffff5bb1); /**//* 11 */
FF (*b, *c, *d, *a, x[11], 22, 0x895cd7be); /**//* 12 */
FF (*a, *b, *c, *d, x[12], 7, 0x6b901122); /**//* 13 */
FF (*d, *a, *b, *c, x[13], 12, 0xfd987193); /**//* 14 */
FF (*c, *d, *a, *b, x[14], 17, 0xa679438e); /**//* 15 */
FF (*b, *c, *d, *a, x[15], 22, 0x49b40821); /**//* 16 */

/**//* Round 2 */
GG (*a, *b, *c, *d, x[ 1], 5, 0xf61e2562); /**//* 17 */
GG (*d, *a, *b, *c, x[ 6], 9, 0xc040b340); /**//* 18 */
GG (*c, *d, *a, *b, x[11], 14, 0x265e5a51); /**//* 19 */
GG (*b, *c, *d, *a, x[ 0], 20, 0xe9b6c7aa); /**//* 20 */
GG (*a, *b, *c, *d, x[ 5], 5, 0xd62f105d); /**//* 21 */
GG (*d, *a, *b, *c, x[10], 9, 0x02441453); /**//* 22 */
GG (*c, *d, *a, *b, x[15], 14, 0xd8a1e681); /**//* 23 */
GG (*b, *c, *d, *a, x[ 4], 20, 0xe7d3fbc8); /**//* 24 */
GG (*a, *b, *c, *d, x[ 9], 5, 0x21e1cde6); /**//* 25 */
GG (*d, *a, *b, *c, x[14], 9, 0xc33707d6); /**//* 26 */
GG (*c, *d, *a, *b, x[ 3], 14, 0xf4d50d87); /**//* 27 */
GG (*b, *c, *d, *a, x[ 8], 20, 0x455a14ed); /**//* 28 */
GG (*a, *b, *c, *d, x[13], 5, 0xa9e3e905); /**//* 29 */
GG (*d, *a, *b, *c, x[ 2], 9, 0xfcefa3f8); /**//* 30 */
GG (*c, *d, *a, *b, x[ 7], 14, 0x676f02d9); /**//* 31 */
GG (*b, *c, *d, *a, x[12], 20, 0x8d2a4c8a); /**//* 32 */

/**//* Round 3 */
HH (*a, *b, *c, *d, x[ 5], 4, 0xfffa3942); /**//* 33 */
HH (*d, *a, *b, *c, x[ 8], 11, 0x8771f681); /**//* 34 */
HH (*c, *d, *a, *b, x[11], 16, 0x6d9d6122); /**//* 35 */
HH (*b, *c, *d, *a, x[14], 23, 0xfde5380c); /**//* 36 */
HH (*a, *b, *c, *d, x[ 1], 4, 0xa4beea44); /**//* 37 */
HH (*d, *a, *b, *c, x[ 4], 11, 0x4bdecfa9); /**//* 38 */
HH (*c, *d, *a, *b, x[ 7], 16, 0xf6bb4b60); /**//* 39 */
HH (*b, *c, *d, *a, x[10], 23, 0xbebfbc70); /**//* 40 */
HH (*a, *b, *c, *d, x[13], 4, 0x289b7ec6); /**//* 41 */
HH (*d, *a, *b, *c, x[ 0], 11, 0xeaa127fa); /**//* 42 */
HH (*c, *d, *a, *b, x[ 3], 16, 0xd4ef3085); /**//* 43 */
HH (*b, *c, *d, *a, x[ 6], 23, 0x04881d05); /**//* 44 */
HH (*a, *b, *c, *d, x[ 9], 4, 0xd9d4d039); /**//* 45 */
HH (*d, *a, *b, *c, x[12], 11, 0xe6db99e5); /**//* 46 */
HH (*c, *d, *a, *b, x[15], 16, 0x1fa27cf8); /**//* 47 */
HH (*b, *c, *d, *a, x[ 2], 23, 0xc4ac5665); /**//* 48 */

/**//* Round 4 */
II (*a, *b, *c, *d, x[ 0], 6, 0xf4292244); /**//* 49 */
II (*d, *a, *b, *c, x[ 7], 10, 0x432aff97); /**//* 50 */
II (*c, *d, *a, *b, x[14], 15, 0xab9423a7); /**//* 51 */
II (*b, *c, *d, *a, x[ 5], 21, 0xfc93a039); /**//* 52 */
II (*a, *b, *c, *d, x[12], 6, 0x655b59c3); /**//* 53 */
II (*d, *a, *b, *c, x[ 3], 10, 0x8f0ccc92); /**//* 54 */
II (*c, *d, *a, *b, x[10], 15, 0xffeff47d); /**//* 55 */
II (*b, *c, *d, *a, x[ 1], 21, 0x85845dd1); /**//* 56 */
II (*a, *b, *c, *d, x[ 8], 6, 0x6fa87e4f); /**//* 57 */
II (*d, *a, *b, *c, x[15], 10, 0xfe2ce6e0); /**//* 58 */
II (*c, *d, *a, *b, x[ 6], 15, 0xa3014314); /**//* 59 */
II (*b, *c, *d, *a, x[13], 21, 0x4e0811a1); /**//* 60 */
II (*a, *b, *c, *d, x[ 4], 6, 0xf7537e82); /**//* 61 */
II (*d, *a, *b, *c, x[11], 10, 0xbd3af235); /**//* 62 */
II (*c, *d, *a, *b, x[ 2], 15, 0x2ad7d2bb); /**//* 63 */
II (*b, *c, *d, *a, x[ 9], 21, 0xeb86d391); /**//* 64 */

*A += *a;
*B += *b;
*C += *c;
*D += *d;

}

void get_x(char *p_str, unsigned *pa_x)
{
int k = 0;
int i = 0;
int j;
int f = 0;
int g,h;
while (p_str[k] != 0)
{
g = k+3;
while (i < 4)
{
if (p_str[g] == 0)
{
g--;
i++;

continue;
}
pa_x[f] = pa_x[f]*16*16+p_str[g];
i++;
g--;
k++;

}
f++;
i = 0;

}
}

int main()
{
char ch[7] = "123456";

char *p;
p = ch;
int f = 0, j;
unsigned A,B,C,D,a,b,c,d,i,len,flen[2],x[16]; //i臨時變數,len文件長,flen[2]為64位二進製表示的文件初始長度
A = 0x67452301, B = 0xefcdab89, C = 0x98badcfe, D = 0x10325476; //初始化鏈接變數
len = strlen(p);
flen[1] = len / 0x20000000; //flen單位是bit
flen[0] = (len % 0x20000000) * 8;
memset(x,0,64); //初始化x數組為0

get_x(ch, x);
for(i=0;i<len/64;i++)
{ //循環運算直至文件結束
go_md5(&a,&b,&c,&d,&A,&B,&C,&D,x);
memset(x,0,64);
get_x(ch, x);
}
((char*)x)[len % 64] = 128;
if(len%64>55)
{
go_md5(&a,&b,&c,&d,&A,&B,&C,&D,x);
memset(x,0,64);
}
memcpy(x + 14, flen, 8);
go_md5(&a,&b,&c,&d,&A,&B,&C,&D,x);
printf("MD5 Code:%08x%08x%08x%08x\n",PP(A),PP(B),PP(C),PP(D));
getch();
return 0;
}
我自己修改的，在devcpp通過，

❺ C語言求文件MD5的函數用法

C語言沒有內置的MD5函數，可以在以下頁面找到C語言實現版程序和MD5的演算法介權紹：

http://tools.ietf.org/html/rfc1321

❻ 如何對字元串進行MD5加密,用C語言實現,給出源代碼和加密函數

/*四個32bits數,用於存放最終計算得到的消息摘要.當消息長度>512bits時,也用於存放每個512bits的中間結果*/ UINT4 state[4]; /*存儲原始信息的bits數長度,不包括填充的bits,最長為2^64 bits*/ UINT4 count[2]; /*存放輸入的信息的緩沖區,512bits*/ unsigned char buffer[64];} MD5_CTX;static void MD5Transform(UINT4[4], unsigned char[64]); static void Encode(unsigned char *, UINT4 *, unsigned int); static void Decode(UINT4 *, unsigned char *, unsigned int);/*用於bits填充的緩沖區,當欲加密的信息的bits數被512除其餘數為448時,需要填充的bits的最大值為512=64*8*/ static unsigned char PADDING[64] = { 0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0};/*接下來的這幾個宏定義是md5演算法規定的,就是對信息進行md5加密都要做的運算*/ #define F(x, y, z) (((x) & (y)) | ((~x) & (z))) #define G(x, y, z) (((x) & (z)) | ((y) & (~z))) #define H(x, y, z) ((x) ^ (y) ^ (z)) #define I(x, y, z) ((y) ^ ((x) | (~z))) #define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32-(n)))) #define FF(a, b, c, d, x, s, ac) {\ (a) += F ((b), (c), (d)) + (x) + (UINT4)(ac);\ (a) = ROTATE_LEFT ((a), (s));\ (a) += (b);\}#define GG(a, b, c, d, x, s, ac) {\ (a) += G ((b), (c), (d)) + (x) + (UINT4)(ac);\ (a) = ROTATE_LEFT ((a), (s));\ (a) += (b);\}#define HH(a, b, c, d, x, s, ac) {\ (a) += H ((b), (c), (d)) + (x) + (UINT4)(ac);\ (a) = ROTATE_LEFT ((a), (s));\ (a) += (b);\}#define II(a, b, c, d, x, s, ac) {\ (a) += I ((b), (c), (d)) + (x) + (UINT4)(ac);\

❼ 如何在Linux下用C語言實現MD5/DES解密

相關庫函數如下：
#include <openssl/md5.h>
unsigned char *MD5(const unsigned char *d, unsigned long n,unsigned char *md);
int MD5_Init(MD5_CTX *c);
int MD5_Update(MD5_CTX *c, const void *data,unsigned long len);
int MD5_Final(unsigned char *md, MD5_CTX *c);

❽ 求生成MD5碼的c或c++代碼

自己用C語言寫的簡單的MD5演算法實現。

#include <stdio.h>
#include <stdlib.h>
#include <memory.h>
#include <math.h>

typedef unsigned char BYTE;
typedef unsigned int UINT;
typedef UINT MD5_SUB_ARRAY[16];
typedef UINT MD5_TRANSORM_FUNC(UINT,UINT,UINT);
typedef struct
{
UINT a;
UINT b;
UINT c;
UINT d;
MD5_SUB_ARRAY sub_array;
}MD5_TRANSFORM_PARAM;

const double MAX_INT = (double)0xFFFFFFFF + 1.0;

const UINT MD5_TRANSFORM_MATRIX[4][16][3] =
{

{
{ 0, 7, 1}, { 1,12, 2}, { 2,17, 3}, { 3,22, 4},
{ 4, 7, 5}, { 5,12, 6}, { 6,17, 7}, { 7,22, 8},
{ 8, 7, 9}, { 9,12,10}, {10,17,11}, {11,22,12},
{12, 7,13}, {13,12,14}, {14,17,15}, {15,22,16},
},

{
{ 1, 5,17}, { 6, 9,18}, {11,14,19}, { 0,20,20},
{ 5, 5,21}, {10, 9,22}, {15,14,23}, { 4,20,24},
{ 9, 5,25}, {14, 9,26}, { 3,14,27}, { 8,20,28},
{13, 5,29}, { 2, 9,30}, { 7,14,31}, {12,20,32},
},

{
{5, 4, 33}, { 8,11,34}, {11,16,35},{14, 23,36},
{1, 4, 37}, { 4,11,38}, { 7,16,39},{10, 23,40},
{13,4, 41}, { 0,11,42}, { 3,16,43},{ 6, 23,44},
{9, 4, 45}, {12,11,46}, {15,16,47},{ 2, 23,48},
},

{
{ 0,6,49}, { 7,10,50}, {14,15,51},{ 5, 21,52},
{12,6,53}, { 3,10,54}, {10,15,55},{ 1, 21,56},
{ 8,6,57}, {15,10,58}, { 6,15,59},{13, 21,60},
{ 4,6,61}, {11,10,62}, { 2,15,63},{ 9, 21,64},
},
};

static UINT MD5_TRANSFORM_ARRAY[65];

void MD5_Init()
{
int x;
for(x = 1; x <= 64; x++)
{
MD5_TRANSFORM_ARRAY[x] = (UINT)(MAX_INT * fabs(sin(x)));
}
}

UINT F(UINT x,UINT y,UINT z)
{
return ((x & y) | ((~x) & z));
}

UINT G(UINT x,UINT y,UINT z)
{
return ((x & z) | (y & (~z)));
}

UINT H(UINT x,UINT y,UINT z)
{
return (x ^ y ^ z);
}

UINT I(UINT x,UINT y,UINT z)
{
return (y ^ (x | (~z)));
}

BYTE* MD5_prepare_data(const BYTE* data,int len,int* new_len)
{
int rest,fill,size;
BYTE* new_data;
UINT bit_len;

// (1) 位元組補齊
rest = len % 56;
if (rest <= 56) fill = 56 - rest;
else fill = (64 - rest) + 56;

new_data = (BYTE*)malloc(len + fill + 8);
if (NULL == new_data) return NULL;

if (len > 0) memcpy(new_data,data,len);
if (fill > 0) memset(new_data + len,0x80,1);
if (fill > 1) memset(new_data + len + 1,0,fill - 1);

size = fill + len;

// (2) 附加數據的比特長度
bit_len = len * 8;
// (64位二進制數表示的)比特長度的低32位
memset(new_data + size + 0,(bit_len & 0x000000FF), 1);
memset(new_data + size + 1,(bit_len & 0x0000FF00) >> 8, 1);
memset(new_data + size + 2,(bit_len & 0x00FF0000) >> 16,1);
memset(new_data + size + 3,(bit_len & 0xFF000000) >> 24,1);
// 不考慮比特長度超出32位無符號數表示範圍,所以高32位總是0
memset(new_data + size + 4,0,4);

*new_len = size + 8;

return new_data;
}

void MD5_transform(MD5_TRANSFORM_PARAM* param,int ring,MD5_TRANSORM_FUNC func)
{
UINT a,b,c,d,s,k,i;
UINT abcd[4];
UINT *X,*T;
int index;

abcd[0] = param->a;
abcd[1] = param->b;
abcd[2] = param->c;
abcd[3] = param->d;
X = param->sub_array;
T = MD5_TRANSFORM_ARRAY;

for(index = 0; index < 16; index++)
{
a = abcd[(3 * index + 0) % 4];
b = abcd[(3 * index + 1) % 4];
c = abcd[(3 * index + 2) % 4];
d = abcd[(3 * index + 3) % 4];

k = MD5_TRANSFORM_MATRIX[ring][index][0];
s = MD5_TRANSFORM_MATRIX[ring][index][1];
i = MD5_TRANSFORM_MATRIX[ring][index][2];

a = a + func(b,c,d) + X[k] + T[i];
a = ( a << s) | ( a >> (32 - s)); // 循環左移
a = a + b;

abcd[(3 * index + 0) % 4] = a;
}

param->a = abcd[0];
param->b = abcd[1];
param->c = abcd[2];
param->d = abcd[3];
}

int MD5(const BYTE* data,int len)
{
int x,y,new_len;
MD5_TRANSFORM_PARAM param;
UINT AA,BB,CC,DD;
BYTE* buf;

MD5_Init();

buf = MD5_prepare_data(data,len,&new_len);
if (buf == NULL) return -1;

AA = 0x67452301;
BB = 0xefcdab89;
CC = 0x98badcfe;
DD = 0x10325476;

for(x = 0; x < new_len / 64; x++)
{
param.a = AA;
param.b = BB;
param.c = CC;
param.d = DD;

for(y = 0; y < 16; y++)
{
param.sub_array[y] = buf[64 * x + 4 * y + 0];
param.sub_array[y] += buf[64 * x + 4 * y + 1] << 8;
param.sub_array[y] += buf[64 * x + 4 * y + 2] << 16;
param.sub_array[y] += buf[64 * x + 4 * y + 3] << 24;
}
MD5_transform(¶m,0,F);
MD5_transform(¶m,1,G);
MD5_transform(¶m,2,H);
MD5_transform(¶m,3,I);

AA += param.a;
BB += param.b;
CC += param.c;
DD += param.d;
}

printf("MD5(\"%s\")=",data);

printf("%02X%02X%02X%02X",
(AA & 0x000000FF),
(AA & 0x0000FF00) >> 8,
(AA & 0x00FF0000) >> 16,
(AA & 0xFF000000) >> 24);

printf("%02X%02X%02X%02X",
(BB & 0x000000FF),
(BB & 0x0000FF00) >> 8,
(BB & 0x00FF0000) >> 16,
(BB & 0xFF000000) >> 24);

printf("%02X%02X%02X%02X",
(CC & 0x000000FF),
(CC & 0x0000FF00) >> 8,
(CC & 0x00FF0000) >> 16,
(CC & 0xFF000000) >> 24);

printf("%02X%02X%02X%02X",
(DD & 0x000000FF),
(DD & 0x0000FF00) >> 8,
(DD & 0x00FF0000) >> 16,
(DD & 0xFF000000) >> 24);

printf("\n");

return 0;
}

int main()
{
MD5("",0);
MD5("a",1);
MD5("abc",3);
MD5("message digest",14);
MD5("abcdefghijklmnopqrstuvwxyz",26);

return 0;
}

❾ C語言怎麼實現對一長串字元進行MD5加密

#include<stdio.h>
#include<stdlib.h>

#defineARR_LEN100

#defineF(x,y,z)((x&y)|(~x&z))
#defineG(x,y,z)((x&z)|(y&~z))
#defineH(x,y,z)(x^y^z)
#defineI(x,y,z)(y^(x|~z))
#defineROTATE_LEFT(x,n)((x<<n)|(x>>(32-n)))
#defineFF(a,b,c,d,x,s,ac)
{
a+=F(b,c,d)+x+ac;
a=ROTATE_LEFT(a,s);
a+=b;
}
#defineGG(a,b,c,d,x,s,ac)
{
a+=G(b,c,d)+x+ac;
a=ROTATE_LEFT(a,s);
a+=b;
}
#defineHH(a,b,c,d,x,s,ac)
{
a+=H(b,c,d)+x+ac;
a=ROTATE_LEFT(a,s);
a+=b;
}
#defineII(a,b,c,d,x,s,ac)
{
a+=I(b,c,d)+x+ac;
a=ROTATE_LEFT(a,s);
a+=b;
}

typedefstruct{
unsignedintcount[2];
unsignedintstate[4];
unsignedcharbuffer[64];
}MD5_CTX;

voidMD5Init(MD5_CTX*context);
voidMD5Update(MD5_CTX*context,unsignedchar*input,unsignedintinputlen);
voidMD5Final(MD5_CTX*context,unsignedchardigest[16]);
voidMD5Transform(unsignedintstate[4],unsignedcharblock[64]);
voidMD5Encode(unsignedchar*output,unsignedint*input,unsignedintlen);
voidMD5Decode(unsignedint*output,unsignedchar*input,unsignedintlen);

unsignedcharPADDING[]={
						0x80,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
						0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
						0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
						0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
};

voidMD5Init(MD5_CTX*context){
	context->count[0]=0;
	context->count[1]=0;
	context->state[0]=0x67452301;
	context->state[1]=0xEFCDAB89;
	context->state[2]=0x98BADCFE;
	context->state[3]=0x10325476;
}

voidMD5Update(MD5_CTX*context,unsignedchar*input,unsignedintinputlen){
	unsignedinti=0,index=0,partlen=0;
	index=(context->count[0]>>3)&0x3F;
partlen=64-index;
context->count[0]+=inputlen<<3;
if(context->count[0]<(inputlen<<3))
		context->count[1]++;
context->count[1]+=inputlen>>29;
	
if(inputlen>=partlen){
memcpy(&context->buffer[index],input,partlen);
MD5Transform(context->state,context->buffer);
for(i=partlen;i+64<=inputlen;i+=64)
MD5Transform(context->state,&input[i]);
index=0;
}
else{
i=0;
}
memcpy(&context->buffer[index],&input[i],inputlen-i);
}

voidMD5Final(MD5_CTX*context,unsignedchardigest[16]){
	unsignedintindex=0,padlen=0;
unsignedcharbits[8];
index=(context->count[0]>>3)&0x3F;
padlen=(index<56)?(56-index):(120-index);
MD5Encode(bits,context->count,8);
MD5Update(context,PADDING,padlen);
MD5Update(context,bits,8);
MD5Encode(digest,context->state,16);
}

voidMD5Encode(unsignedchar*output,unsignedint*input,unsignedintlen){
unsignedinti=0,j=0;
while(j<len){
		output[j]=input[i]&0xFF;
		output[j+1]=(input[i]>>8)&0xFF;
		output[j+2]=(input[i]>>16)&0xFF;
		output[j+3]=(input[i]>>24)&0xFF;
		i++;
		j+=4;
}
}

voidMD5Decode(unsignedint*output,unsignedchar*input,unsignedintlen){
unsignedinti=0,j=0;
while(j<len){
		output[i]=(input[j])|
					(input[j+1]<<8)|
					(input[j+2]<<16)|
					(input[j+3]<<24);
		i++;
		j+=4;
}
}

voidMD5Transform(unsignedintstate[4],unsignedcharblock[64]){
	unsignedinta=state[0];
	unsignedintb=state[1];
	unsignedintc=state[2];
	unsignedintd=state[3];
	unsignedintx[64];
	MD5Decode(x,block,64);
	FF(a,b,c,d,x[0],7,0xd76aa478);/*1*/
	FF(d,a,b,c,x[1],12,0xe8c7b756);/*2*/
	FF(c,d,a,b,x[2],17,0x242070db);/*3*/
	FF(b,c,d,a,x[3],22,0xc1bdceee);/*4*/
	FF(a,b,c,d,x[4],7,0xf57c0faf);/*5*/
	FF(d,a,b,c,x[5],12,0x4787c62a);/*6*/
	FF(c,d,a,b,x[6],17,0xa8304613);/*7*/
	FF(b,c,d,a,x[7],22,0xfd469501);/*8*/
	FF(a,b,c,d,x[8],7,0x698098d8);/*9*/
	FF(d,a,b,c,x[9],12,0x8b44f7af);/*10*/
	FF(c,d,a,b,x[10],17,0xffff5bb1);/*11*/
	FF(b,c,d,a,x[11],22,0x895cd7be);/*12*/
	FF(a,b,c,d,x[12],7,0x6b901122);/*13*/
	FF(d,a,b,c,x[13],12,0xfd987193);/*14*/
	FF(c,d,a,b,x[14],17,0xa679438e);/*15*/
	FF(b,c,d,a,x[15],22,0x49b40821);/*16*/

	/*Round2*/
	GG(a,b,c,d,x[1],5,0xf61e2562);/*17*/
	GG(d,a,b,c,x[6],9,0xc040b340);/*18*/
	GG(c,d,a,b,x[11],14,0x265e5a51);/*19*/
	GG(b,c,d,a,x[0],20,0xe9b6c7aa);/*20*/
	GG(a,b,c,d,x[5],5,0xd62f105d);/*21*/
	GG(d,a,b,c,x[10],9,0x2441453);/*22*/
	GG(c,d,a,b,x[15],14,0xd8a1e681);/*23*/
	GG(b,c,d,a,x[4],20,0xe7d3fbc8);/*24*/
	GG(a,b,c,d,x[9],5,0x21e1cde6);/*25*/
	GG(d,a,b,c,x[14],9,0xc33707d6);/*26*/
	GG(c,d,a,b,x[3],14,0xf4d50d87);/*27*/
	GG(b,c,d,a,x[8],20,0x455a14ed);/*28*/
	GG(a,b,c,d,x[13],5,0xa9e3e905);/*29*/
	GG(d,a,b,c,x[2],9,0xfcefa3f8);/*30*/
	GG(c,d,a,b,x[7],14,0x676f02d9);/*31*/
	GG(b,c,d,a,x[12],20,0x8d2a4c8a);/*32*/

	/*Round3*/
	HH(a,b,c,d,x[5],4,0xfffa3942);/*33*/
	HH(d,a,b,c,x[8],11,0x8771f681);/*34*/
	HH(c,d,a,b,x[11],16,0x6d9d6122);/*35*/
	HH(b,c,d,a,x[14],23,0xfde5380c);/*36*/
	HH(a,b,c,d,x[1],4,0xa4beea44);/*37*/
	HH(d,a,b,c,x[4],11,0x4bdecfa9);/*38*/
	HH(c,d,a,b,x[7],16,0xf6bb4b60);/*39*/
	HH(b,c,d,a,x[10],23,0xbebfbc70);/*40*/
	HH(a,b,c,d,x[13],4,0x289b7ec6);/*41*/
	HH(d,a,b,c,x[0],11,0xeaa127fa);/*42*/
	HH(c,d,a,b,x[3],16,0xd4ef3085);/*43*/
	HH(b,c,d,a,x[6],23,0x4881d05);/*44*/
	HH(a,b,c,d,x[9],4,0xd9d4d039);/*45*/
	HH(d,a,b,c,x[12],11,0xe6db99e5);/*46*/
	HH(c,d,a,b,x[15],16,0x1fa27cf8);/*47*/
	HH(b,c,d,a,x[2],23,0xc4ac5665);/*48*/

	/*Round4*/
	II(a,b,c,d,x[0],6,0xf4292244);/*49*/
	II(d,a,b,c,x[7],10,0x432aff97);/*50*/
	II(c,d,a,b,x[14],15,0xab9423a7);/*51*/
	II(b,c,d,a,x[5],21,0xfc93a039);/*52*/
	II(a,b,c,d,x[12],6,0x655b59c3);/*53*/
	II(d,a,b,c,x[3],10,0x8f0ccc92);/*54*/
	II(c,d,a,b,x[10],15,0xffeff47d);/*55*/
	II(b,c,d,a,x[1],21,0x85845dd1);/*56*/
	II(a,b,c,d,x[8],6,0x6fa87e4f);/*57*/
	II(d,a,b,c,x[15],10,0xfe2ce6e0);/*58*/
	II(c,d,a,b,x[6],15,0xa3014314);/*59*/
	II(b,c,d,a,x[13],21,0x4e0811a1);/*60*/
	II(a,b,c,d,x[4],6,0xf7537e82);/*61*/
	II(d,a,b,c,x[11],10,0xbd3af235);/*62*/
	II(c,d,a,b,x[2],15,0x2ad7d2bb);/*63*/
	II(b,c,d,a,x[9],21,0xeb86d391);/*64*/
	state[0]+=a;
	state[1]+=b;
	state[2]+=c;
	state[3]+=d;
}

intmain(intargc,char*argv[]){
inti;
unsignedcharencrypt[ARR_LEN];
unsignedchardecrypt[16];
MD5_CTXmd5;

printf("【測試1】
");
printf("加密前：Bai
");
printf("加密後：
");
printf("
");
printf("【測試2】
");
printf("加密前：Bihaifeng
");
printf("加密後：
");
printf("
");
printf("======================================================

");

printf("請輸入需MD5加密的字元串：
");
gets(encrypt);
printf("
");
printf("======================================================

");

MD5Init(&md5);
MD5Update(&md5,encrypt,strlen((char*)encrypt));
MD5Final(&md5,decrypt);

	printf("加密前：%s
加密後：",encrypt);
for(i=0;i<16;i++){
printf("%02x",decrypt[i]);
}
	printf("
");

getch();
return0;
}

運行結果

以上源代碼非原創~~

❿ 求用c語言實現md5演算法的編程思路

主要就是調用庫函數
MD5加密說到底也是函數計算
沒有什麼思路的問題，了解md5的發明演算法，這應該是一個數學問題

我這里有代碼，你可以參考一下

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <string.h>

typedef unsigned char *POINTER;
typedef unsigned short int UINT2;
typedef unsigned long int UINT4;

typedef struct
{
UINT4 state[4];
UINT4 count[2];
unsigned char buffer[64];
} MD5_CTX;

void MD5Init(MD5_CTX *);
void MD5Update(MD5_CTX *, unsigned char *, unsigned int);
void MD5Final(unsigned char [16], MD5_CTX *);

#define S11 7
#define S12 12
#define S13 17
#define S14 22
#define S21 5
#define S22 9
#define S23 14
#define S24 20
#define S31 4
#define S32 11
#define S33 16
#define S34 23
#define S41 6
#define S42 10
#define S43 15
#define S44 21

static unsigned char PADDING[64] = {
0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
};

#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
#define H(x, y, z) ((x) ^ (y) ^ (z))
#define I(x, y, z) ((y) ^ ((x) | (~z)))

#define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32-(n))))

#define FF(a, b, c, d, x, s, ac) { (a) += F ((b), (c), (d)) + (x) + (UINT4)(ac); (a) = ROTATE_LEFT ((a), (s)); (a) += (b); }
#define GG(a, b, c, d, x, s, ac) { (a) += G ((b), (c), (d)) + (x) + (UINT4)(ac); (a) = ROTATE_LEFT ((a), (s)); (a) += (b); }
#define HH(a, b, c, d, x, s, ac) { (a) += H ((b), (c), (d)) + (x) + (UINT4)(ac); (a) = ROTATE_LEFT ((a), (s)); (a) += (b); }
#define II(a, b, c, d, x, s, ac) { (a) += I ((b), (c), (d)) + (x) + (UINT4)(ac); (a) = ROTATE_LEFT ((a), (s)); (a) += (b); }

inline void Encode(unsigned char *output, UINT4 *input, unsigned int len)
{
unsigned int i, j;

for (i = 0, j = 0; j < len; i++, j += 4) {
output[j] = (unsigned char)(input[i] & 0xff);
output[j+1] = (unsigned char)((input[i] >> 8) & 0xff);
output[j+2] = (unsigned char)((input[i] >> 16) & 0xff);
output[j+3] = (unsigned char)((input[i] >> 24) & 0xff);
}
}

inline void Decode(UINT4 *output, unsigned char *input, unsigned int len)
{
unsigned int i, j;

for (i = 0, j = 0; j < len; i++, j += 4)
output[i] = ((UINT4)input[j]) | (((UINT4)input[j+1]) << 8) |
(((UINT4)input[j+2]) << 16) | (((UINT4)input[j+3]) << 24);
}

inline void MD5Transform (UINT4 state[4], unsigned char block[64])
{
UINT4 a = state[0], b = state[1], c = state[2], d = state[3], x[16];
Decode (x, block, 64);
FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /* 1 */
FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /* 2 */
FF (c, d, a, b, x[ 2], S13, 0x242070db); /* 3 */
FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /* 4 */
FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /* 5 */
FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /* 6 */
FF (c, d, a, b, x[ 6], S13, 0xa8304613); /* 7 */
FF (b, c, d, a, x[ 7], S14, 0xfd469501); /* 8 */
FF (a, b, c, d, x[ 8], S11, 0x698098d8); /* 9 */
FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /* 10 */
FF (c, d, a, b, x[10], S13, 0xffff5bb1); /* 11 */
FF (b, c, d, a, x[11], S14, 0x895cd7be); /* 12 */
FF (a, b, c, d, x[12], S11, 0x6b901122); /* 13 */
FF (d, a, b, c, x[13], S12, 0xfd987193); /* 14 */
FF (c, d, a, b, x[14], S13, 0xa679438e); /* 15 */
FF (b, c, d, a, x[15], S14, 0x49b40821); /* 16 */
GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /* 17 */
GG (d, a, b, c, x[ 6], S22, 0xc040b340); /* 18 */
GG (c, d, a, b, x[11], S23, 0x265e5a51); /* 19 */
GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /* 20 */
GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /* 21 */
GG (d, a, b, c, x[10], S22, 0x2441453); /* 22 */
GG (c, d, a, b, x[15], S23, 0xd8a1e681); /* 23 */
GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /* 24 */
GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /* 25 */
GG (d, a, b, c, x[14], S22, 0xc33707d6); /* 26 */
GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /* 27 */
GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /* 28 */
GG (a, b, c, d, x[13], S21, 0xa9e3e905); /* 29 */
GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /* 30 */
GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /* 31 */
GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /* 32 */
HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /* 33 */
HH (d, a, b, c, x[ 8], S32, 0x8771f681); /* 34 */
HH (c, d, a, b, x[11], S33, 0x6d9d6122); /* 35 */
HH (b, c, d, a, x[14], S34, 0xfde5380c); /* 36 */
HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /* 37 */
HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /* 38 */
HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /* 39 */
HH (b, c, d, a, x[10], S34, 0xbebfbc70); /* 40 */
HH (a, b, c, d, x[13], S31, 0x289b7ec6); /* 41 */
HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /* 42 */
HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /* 43 */
HH (b, c, d, a, x[ 6], S34, 0x4881d05); /* 44 */
HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /* 45 */
HH (d, a, b, c, x[12], S32, 0xe6db99e5); /* 46 */
HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /* 47 */
HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /* 48 */
II (a, b, c, d, x[ 0], S41, 0xf4292244); /* 49 */
II (d, a, b, c, x[ 7], S42, 0x432aff97); /* 50 */
II (c, d, a, b, x[14], S43, 0xab9423a7); /* 51 */
II (b, c, d, a, x[ 5], S44, 0xfc93a039); /* 52 */
II (a, b, c, d, x[12], S41, 0x655b59c3); /* 53 */
II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /* 54 */
II (c, d, a, b, x[10], S43, 0xffeff47d); /* 55 */
II (b, c, d, a, x[ 1], S44, 0x85845dd1); /* 56 */
II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /* 57 */
II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /* 58 */
II (c, d, a, b, x[ 6], S43, 0xa3014314); /* 59 */
II (b, c, d, a, x[13], S44, 0x4e0811a1); /* 60 */
II (a, b, c, d, x[ 4], S41, 0xf7537e82); /* 61 */
II (d, a, b, c, x[11], S42, 0xbd3af235); /* 62 */
II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /* 63 */
II (b, c, d, a, x[ 9], S44, 0xeb86d391); /* 64 */
state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;
memset ((POINTER)x, 0, sizeof (x));
}

inline void MD5Init(MD5_CTX *context)
{
context->count[0] = context->count[1] = 0;
context->state[0] = 0x67452301;
context->state[1] = 0xefcdab89;
context->state[2] = 0x98badcfe;
context->state[3] = 0x10325476;
}

inline void MD5Update(MD5_CTX *context, unsigned char *input, unsigned int inputLen)
{
unsigned int i, index, partLen;

index = (unsigned int)((context->count[0] >> 3) & 0x3F);
if ((context->count[0] += ((UINT4)inputLen << 3))
< ((UINT4)inputLen << 3))
context->count[1]++;
context->count[1] += ((UINT4)inputLen >> 29);

partLen = 64 - index;

if (inputLen >= partLen) {
memcpy((POINTER)&context->buffer[index], (POINTER)input, partLen);
MD5Transform(context->state, context->buffer);

for (i = partLen; i + 63 < inputLen; i += 64)
MD5Transform (context->state, &input[i]);
index = 0;
}
else
i = 0;

memcpy((POINTER)&context->buffer[index], (POINTER)&input[i], inputLen-i);
}

inline void MD5Final(unsigned char digest[16], MD5_CTX *context)
{
unsigned char bits[8];
unsigned int index, padLen;

Encode (bits, context->count, 8);
index = (unsigned int)((context->count[0] >> 3) & 0x3f);
padLen = (index < 56) ? (56 - index) : (120 - index);
MD5Update (context, PADDING, padLen);
MD5Update (context, bits, 8);
Encode (digest, context->state, 16);
memset ((POINTER)context, 0, sizeof (*context));
}

void MD5Digest(char *pszInput, unsigned long nInputSize, char *pszOutPut)
{
MD5_CTX context;
unsigned int len = strlen (pszInput);

MD5Init (&context);
MD5Update (&context, (unsigned char *)pszInput, len);
MD5Final ((unsigned char *)pszOutPut, &context);
}

main()
{ char szDigest[16];
char encrypt[200];
printf("請輸入要計算MD5值的字元串:");
gets(encrypt);
printf("\n加密結果:");
MD5Digest(encrypt,strlen(encrypt),szDigest);
int i;
for (i=0;i<16;i++) printf ("%02X",(unsigned char)szDigest[i]);
getchar();
}

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md5c語言實現

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