① 与javabean,jsp,b/s构架 有关的论文参考文献

[1]飞思科技产品研发中心.JSP应用开发详解(第二版)[M].北京:电子工业出版社,
[2]吴以欣,陈小宁.JavaScript 脚本程序设计[M].北京:人民邮电出版社,2005
[3]萨师煊,王珊.数据库系统概论(第三版) [M].北京:高等教育出版社, 2000
[4] 孙卫琴、李洪成.Tomcat与Java Web开发技术详解[M].北京:电子工业出版社,2004
[5] 曾云飞 ,基于Struts框架的电子政务研究和实现 [M].东北大学出版社 2005
[6]程凯.JSP中文问题及一套整体解决方案[J].许昌学院学报,2006,25(5):77-80.
[7]刘长生,谢强,丁秋林.Java应用中的汉字乱码问题分析[J].计算机技术与发展,2006,16(1):158-161
[8]乐秀潘,沈琴.structs1.1与struct1s.2的比较[J].电力系统通信.2000,20(5):35—39
[9]孙东卫,张冀红,李声利. 数据库访问技术研究[J].现代电子技术.2002,18(5).20-34.
[10] 苟凌怡,魏生民. SQL Server 中索引的有效选取[J].计算机工程与应用, 1999,35(6): 70-71
[11] 张树亮, 李超.ASP.NET 2.0+SQL Server网络应用系统开发案例精解[M].北京:清华大学出版社,2006
[12] G.E.Hobona, S.J.Abele, Philip James [J]. University of Newcastle upon Tyne, 2006
[13] Mark Wutka,Alan Moffet,Kunal Mittal.Sams Teach Yourself JAVAServer Pages 2.0 with Apache Tomcat in 24 Hours[M].Sams Publishing,2003
[14]James Turner,Kevin Bedell. Struts Kick Start[M]. SAMS,2004
[15] Kong Michael. An environment for secure SQL/Server computing [M].Oxford University Press Inc., 1993: 149

[1] 程凯. 计算机技术与应用研究[J]. 许昌学院学报,2006, 25(5):77-80
[2] 赵川,丁志刚,宗宇伟等. 基于Eclipse的测试工具管理平台构建[J]. 软件世界, 2006年 14期:78-79
[3] 张红梅,王磊. 计算机及网络技术应用[J]. 实验科学与技术 ,2006,4(4):39-40,50
[4] 郝艳芳,廉永健. 制造业信息化[J].机电产品开发与创新 ,2006,19(4):110-112
[5] 任永功,王政军. 软件技术与数据库[J]. 计算机工程 ,2006,32(5):60-62,134
[6] 孙琳、李素芬. 计算机应用研究[J]. 计算机技术与发展 ,2006,16(4):209-211,214
[7] 张宁等. 生物技术[J]. 高技术通讯,2006,16[12]: 1289-1293
[8] 刘杰. Eclipse下插件的设计方法[J]. 程序员 ,2006(5):57-59
[9] 张红梅,王磊. 在JSP中访问数据库的方法[J]. 农业图书情报学刊, 2006,18(12):142-144
[10] 张宁,吴捷,杨卓,张涛. 基于SQL Server的脑电数据库的构建[J]. 广西科学院学报 ,2006 22(4):275-278
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[14] Sanden, Bo. SYSTEMS PROGRAMMING WITH JSP:EXAMPLE - A VDU CONTROLLER[C]. Communications of the ACM,Vol28,No10,1985:1059-1067
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② 杭电ACM 1002 java老是报错

题里说了数字会非常大,超出32位整形范围,你用long肯定不行的,对大数的处理上java比C要简单很多,你直接用java的BigInteger类就可以了

③ 有关acm算法的一道java题

importjava.util.Scanner;

publicclassFrogs{
publicstaticvoidmain(String[]args){
Scannersc=newScanner(System.in);
System.out.println("pleaseinputtheKandthenpress"Enter"");
intk=sc.nextInt();
System.out.println("pleaseinputtheSandthenpress"Enter"");
ints=sc.nextInt();
printFrogs(k,s);
sc.close();
}
publicstaticvoidprintFrogs(intk,ints){
for(;k<=s;k++){
System.out.print(k+"froghas"+k+"mouth,"+k*2+"eyesand"+k*4+"legs,");
System.out.println(".");
}
}
}

修改了下,你可以自己输入S和K

④ 用java解的ACM题目求改正

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

public class Test {

public static List<Integer> countWord(String input, int numOfWords, String[] targets) {
String[] split = input.split(" ");
Map<String, Integer> targets_map = new HashMap<>();
for (String target : targets) {
targets_map.put(target, 0);
}
for (String search : split) {
if (targets_map.containsKey(search)) {
targets_map.put(search, targets_map.get(search) + 1);
}
}
List<Integer> result = new ArrayList<>();
for (int i = 0; i < targets.length; i++) {
result.add(targets_map.get(targets[i]));
}
return result;
}

public static void main(String[] args) {
String[] targets = new String[]{"Neusoft", "a"};
List<Integer> result = Test.countWord("Dalian Neusoft University of Information is a private university founded by Neusoft with the Ministry of Ecation is approval.\u200B DNUI, with a strong focus on engineering, offers tertiary ecation programs across a number of disciplines including engineering, management, digital art, foreign languages and healthcare technology.The campus is located in Dalian, a beautiful coastal city in Northeastern China.", 2, targets);
for (int res : result) {
System.out.println(res);
}
}
}

⑤ 杭电ACM 1005 java

if (a < 1 && a > 1000 && b < 1 && b > 1000 && b < 1 && a > 100000000)
System.exit(0);
这句你用的是& 不对 还有就是你这个做法不行 BigInteger f[] = new BigInteger[n]; 当n=100000000时开不了这么大的数组 时间复杂度也不行 必定超时

⑥ 急!求一道航电的ACM题的正确答案!

注意这题可能有个陷阱, 就是某个仓库的f==0的情况要考虑进去
AC的代码如下(注意用G++提交):

#include <iostream>
#include <queue>
using namespace std;

struct Food {int j, f;} food[100003];
int m, n;
double ans;

bool cmp(const Food &a, const Food &b)
{
return a.j*b.f > b.j*a.f;
}

int main()
{
while (scanf("%d%d", &m, &n), !(m==-1 && n==-1))
{
for (int i=0; i<n; i++) scanf("%d%d", &food[i].j, &food[i].f);
sort(food, food+n, cmp), ans = 0;
for (int i=0; i<n; i++)
{
if (food[i].f == 0) ans += food[i].j;
else if (m >= food[i].f) ans += food[i].j, m -= food[i].f;
else { ans += (double)m / food[i].f * food[i].j; break;}
}
printf("%.3lf\n", ans);
}
}

⑦ java 程序...最好用 ACM写,不行的话,就随意..谢谢..

import java.util.InputMismatchException;
import java.util.Scanner;

public class Cat {

public static void main(String[] args) {

System.out.println("*****Please input an integer between 2 and 7: ****");
Scanner scanner = new Scanner(System.in);

int value = getInputInteger(scanner);

//for better performance, we calc their lowest common multiple
int lowestCommonMultiple = (value % 2 == 0 ? value: 2*value);

for(int i = lowestCommonMultiple; i <= 90; i += lowestCommonMultiple){
System.out.print(i + "\t");
}

}

private static int getInputInteger(Scanner scanner) {
int valueInput = 0;

try {
valueInput = scanner.nextInt();

if(valueInput < 2 || valueInput > 7){
System.out.println("Invalid value, please input an integer value between 2 and 7: ");
getInputInteger(scanner);
}else{
return valueInput;
}

} catch (InputMismatchException unmatchExp) {
System.out.println("Invalid value, please input an integer value between 2 and 7: ");
getInputInteger(scanner);
}

return valueInput;
}

}